A) \[0.2,\text{ }22.\text{ }20\]
B) \[0.2,\text{ }11\text{ }.11\]
C) \[0.167,\text{ }11.\text{ }11\]
D) \[0.167,\text{ }22.20\]
Correct Answer: C
Solution :
| Moles of \[NaOH=\frac{8}{40}=0.2\] |
| Moles of \[{{H}_{2}}O=\frac{18}{18}=1\] |
| Mole fraction of \[NaOH=\frac{0.2}{1.2}=0.167\] |
| Molality \[=\frac{8}{40}\times \frac{1000}{18}=11.11.\] |
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