KVPY Sample Paper KVPY Stream-SX Model Paper-21

  • question_answer
    \[{{H}_{2}}O.\] Mole fraction of \[NaOH\] in solution and molality \[(in\,mol\,k{{g}^{-1}})\] of the solution respectively are:

    A) \[0.2,\text{ }22.\text{ }20\]

    B) \[0.2,\text{ }11\text{ }.11\]

    C) \[0.167,\text{ }11.\text{ }11\]

    D) \[0.167,\text{ }22.20\]

    Correct Answer: C

    Solution :

    Moles of   \[NaOH=\frac{8}{40}=0.2\]
    Moles of \[{{H}_{2}}O=\frac{18}{18}=1\]
    Mole fraction of \[NaOH=\frac{0.2}{1.2}=0.167\]
    Molality \[=\frac{8}{40}\times \frac{1000}{18}=11.11.\]

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