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KVPY Sample Paper KVPY Stream-SX Model Paper-21

  • question_answer
    \[\wedge _{m}^{o}\] for \[NaCl,\text{ }HCl\] and \[NaA\] are 126.4, 425.9 and 100.5 \[S\,c{{m}^{2}}mo{{l}^{-1}},\] respectively. If the conductive of \[0.001\text{ }MHA\] is \[5\times {{10}^{-5}}S\,c{{m}^{-1}},\] degree of dissociation of HA is:

    A) 0.50

    B) 0.25

    C) 0.125               

    D) 0.75

    Correct Answer: C

    Solution :

    \[\lambda _{m}^{0}(HA)=100.5+425.9-126.4=400\]
    \[\lambda _{m}^{0}=\frac{K\times 100}{M}=\frac{5\times {{10}^{-5}}\times {{10}^{3}}}{{{10}^{-3}}}=50\]
    \[\alpha =\frac{50}{400}=0.125.\]


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