A) 0.50
B) 0.25
C) 0.125
D) 0.75
Correct Answer: C
Solution :
\[\lambda _{m}^{0}(HA)=100.5+425.9-126.4=400\] |
\[\lambda _{m}^{0}=\frac{K\times 100}{M}=\frac{5\times {{10}^{-5}}\times {{10}^{3}}}{{{10}^{-3}}}=50\] |
\[\alpha =\frac{50}{400}=0.125.\] |
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