A) \[2p-3\]
B) \[-\,1\]
C) \[-\,3-2p\]
D) \[-1+2p\]
Correct Answer: D
Solution :
\[f'\,(x)=-\,2\sin 2x+2p\,\cos x\] |
\[f'\,(x)=-\,2\cos x\,(2\sin x-p)\] |
Since \[p>2\]\[\Rightarrow \]\[2\sin x-p<0\] |
Hence \[f'\,(x)\]will have same sigh as \[\cos \,\,x\] |
Hence maximum value is at \[x=\pi /2\] which is equal to \[-1+2p\] |
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