A) \[{{\cot }^{-1}}x\]
B) \[\pi +{{\cot }^{-1}}x\]
C) \[\pi -{{\cot }^{-1}}x\]
D) \[-\pi +{{\cot }^{-1}}x\]
Correct Answer: D
Solution :
| \[x>0{{\cot }^{-1}}x=t\] |
| \[t\in \left( \frac{\pi }{2},\,\,\pi \right)\] |
| \[\cot \,\,t=x\] |
| \[\tan \,\,t=\frac{1}{x}\] |
| \[{{\tan }^{-1}}\tan ={{\tan }^{-1}}\frac{1}{x}\] |
| \[t-\pi ={{\tan }^{-1}}\frac{1}{x}\] |
| \[-\pi +{{\cot }^{-1}}x={{\tan }^{-1}}\frac{1}{x}.\] |
You need to login to perform this action.
You will be redirected in
3 sec
