| A charged particle (of charge q and mass m) is projected between plates of a parallel plate capacitor as shown at\[t=0\]. Time t at which instantaneous power delivered by the electric field to the particle is zero is |
 |
A) \[\frac{2mu{{\varepsilon }_{0}}\sin \alpha }{q\sigma }\]
B) \[\frac{mu{{\varepsilon }_{0}}\sin \alpha }{q\sigma }\]
C) \[\frac{mu{{\varepsilon }_{0}}\sin \alpha }{2q\sigma }\]
D) \[\frac{mu{{\varepsilon }_{0}}\sin \alpha }{4q\sigma }\]
Correct Answer: B
Solution :
| \[{{u}_{y}}=u\sin \alpha ,{{a}_{y}}=\frac{Eq}{m}=\frac{\sigma q}{{{\varepsilon }_{0}}m}\] |
| Using \[{{v}_{y}}={{u}_{y}}-at,\]we have |
| \[0=u\sin \alpha -\frac{\sigma q}{{{\varepsilon }_{0}}m}t\Rightarrow t=\left( \frac{mu{{\varepsilon }_{0}}\sin \alpha }{q\sigma } \right)\] |
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