• # question_answer A circuit is arranged as shown. At time $\operatorname{t}=0 s,$ switch S is placed in position 1. At  t= 5 s, contact is changed from 1 to 2. The voltage across the capacitor is measured at t = 5 s, and at t = 6 s. Let these voltages be ${{\operatorname{V}}_{1}}$ and ${{\operatorname{V}}_{2}}$ respectively. Then ${{\operatorname{V}}_{1}}$ and ${{\operatorname{V}}_{2}}$ respectively are   A) 10 volt and 0 volt B) 9.18 volt and 3.67 volt C) 9.18 volt and 3.37 volt D) 10 volt and 3.67 volt

 (i) $V={{V}_{0}}\left( 1-{{e}^{-\frac{t}{2RC}}} \right);$ $V={{V}_{0}}\left( 1-{{e}^{-\frac{5}{2}}} \right)=9.18volt$ $V={{V}_{0}}\left( {{e}^{-\frac{t}{RC}}} \right)=9.18{{e}^{-1/1}}$ $=\frac{9.18}{e}=3.37\,volt$