A) \[100\mu \operatorname{A}\]
B) \[.01\operatorname{mA}\]
C) \[500\mu \operatorname{A}\]
D) \[25\operatorname{mA}\]
Correct Answer: C
Solution :
| \[{{i}_{b}}=\frac{V}{{{R}_{1}}}=\frac{0.01}{1\times {{10}^{2}}}={{10}^{-5}}A\] |
| We know that,\[\beta =\frac{{{i}_{c}}}{{{i}_{b}}}\] |
| \[\therefore \] \[{{i}_{c}}=\beta \times {{i}_{b}}\] |
| \[=50\times {{10}^{-5}}=500\mu A\] |
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