• # question_answer The transfer ratio $\beta$ of transistor is 50. The input resistance of a transistor when used in C.E. (common emitter) configuration is $1k\Omega$. The peak value of the collector A.C. current for an A.C. input voltage of 0.01 V peak is A) $100\mu \operatorname{A}$ B) $.01\operatorname{mA}$ C) $500\mu \operatorname{A}$ D) $25\operatorname{mA}$

 ${{i}_{b}}=\frac{V}{{{R}_{1}}}=\frac{0.01}{1\times {{10}^{2}}}={{10}^{-5}}A$ We know that,$\beta =\frac{{{i}_{c}}}{{{i}_{b}}}$ $\therefore$      ${{i}_{c}}=\beta \times {{i}_{b}}$ $=50\times {{10}^{-5}}=500\mu A$