KVPY Sample Paper KVPY Stream-SX Model Paper-22

  • question_answer
    In the reversible reaction,\[2N{{O}_{2}}{{N}_{2}}{{O}_{4}}\]the rate of disappearance of \[N{{O}_{2}}\] is equal to

    A) \[\frac{2{{k}_{1}}}{{{k}_{2}}}{{[N{{O}_{2}}]}^{2}}\]                     

    B) \[2{{k}_{1}}{{[N{{O}_{2}}]}^{2}}-2{{k}_{2}}[{{N}_{2}}{{O}_{4}}]\]

    C) \[2{{k}_{1}}{{[N{{O}_{2}}]}^{2}}-{{k}_{2}}[{{N}_{2}}{{O}_{4}}]\]

    D) \[(2{{k}_{1}}-{{k}_{2}})[N{{O}_{2}}]\]

    Correct Answer: B

    Solution :

    \[2N{{O}_{2}}\underset{{{k}_{2}}}{\overset{{{k}_{1}}}{\longleftrightarrow}}{{N}_{2}}{{O}_{4}}\]
    Rate of reaction of \[=-\frac{1}{2}\frac{d\,[N{{O}_{2}}]}{dt}\]
    \[={{k}_{1}}{{[N{{O}_{2}}]}^{2}}-{{k}^{2}}[{{N}_{2}}{{O}_{4}}]\]
    \[\therefore \,\] Rate of disappearance of \[N{{O}_{2}}\]
    i.e. \[\frac{-d[N{{O}_{2}}]}{dt}=2{{k}_{1}}{{[N{{O}_{2}}]}^{2}}-2{{k}_{2}}[{{N}_{2}}{{O}_{4}}]\]


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