• question_answer  $Xe{{F}_{4}}$ reacts with water at  $-\,80{}^\circ C$  to give A) $XeO{{F}_{2}}$ B) $XeO{{F}_{4}}$ C) $Xe{{O}_{3}}$ D) $Xe{{O}_{2}}{{F}_{2}}$

Xenon tetrafluoride reacts with water at $-80{}^\circ C$ to give xenon oxyfluoride and hydrogen fluoride. $Xe{{F}_{4}}+{{H}_{2}}O\xrightarrow{80{}^\circ C}\underset{\begin{smallmatrix} Xenon \\ oxyfluoride \end{smallmatrix}}{\mathop{XeO{{F}_{2}}}}\,+2HF$