• # question_answer For the reaction, $CaO+2HCl\xrightarrow{{}}CaC{{l}_{2}}+{{H}_{2}}O$ $1.23\,g$of $CaO$is reacted with excess of hydrochloric acid and $1.85\text{ }g$ of $CaC{{l}_{2}}$ is formed. What is the per cent yield? A) 76.1 B) 86.3 C) 95.1 D) None of these

 The balanced equation is $\underset{\begin{smallmatrix} 1mol \\ 56g \end{smallmatrix}}{\mathop{CaO}}\,+2HCL\to \underset{\begin{smallmatrix} 1mol \\ 111g \end{smallmatrix}}{\mathop{CaC{{l}_{2}}}}\,+{{H}_{2}}O$ $56g\,of\,CaO\,produces\,CaC{{l}_{2}}=111g$ $1.23g\,\,of\,CaO\,$will produce$CaC{{l}_{2}}=\frac{111}{56}\times 1.23$ Thus, theoretical yield = 2.43 g Actual yield = 1.85 g Per cent yield $=\frac{1.85}{2.43}\times 100=76.1$