KVPY Sample Paper KVPY Stream-SX Model Paper-22

  • question_answer
    For the reaction,
    \[1.23\,g\]of \[CaO\]is reacted with excess of hydrochloric acid and \[1.85\text{ }g\] of \[CaC{{l}_{2}}\] is formed. What is the per cent yield?

    A) 76.1

    B) 86.3

    C) 95.1

    D) None of these

    Correct Answer: A

    Solution :

    The balanced equation is
    \[\underset{\begin{smallmatrix}  1mol \\  56g \end{smallmatrix}}{\mathop{CaO}}\,+2HCL\to \underset{\begin{smallmatrix}  1mol \\  111g \end{smallmatrix}}{\mathop{CaC{{l}_{2}}}}\,+{{H}_{2}}O\]
    \[1.23g\,\,of\,CaO\,\]will produce\[CaC{{l}_{2}}=\frac{111}{56}\times 1.23\]
    Thus, theoretical yield = 2.43 g
    Actual yield = 1.85 g
    Per cent yield \[=\frac{1.85}{2.43}\times 100=76.1\]

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