A) \[\left( \frac{b}{2a},\,\,\frac{q}{2p} \right)\]
B) \[\left( -\frac{b}{2a},\,\,-\frac{q}{2p} \right)\]
C) \[\left( \frac{b}{a},\,\,\frac{q}{p} \right)\]
D) none of these
Correct Answer: B
Solution :
\[{{x}_{1}}+{{x}_{2}}=-\,b/q\] and \[{{y}_{1}}+{{y}_{2}}=-\,q/p\] |
Centre \[\left[ \frac{{{x}_{1}}+{{x}_{2}}}{2},\,\,\frac{{{y}_{1}}+{{y}_{2}}}{2} \right]\equiv \left[ -\frac{b}{2a},\,\,\frac{-\,q}{2p} \right]\] |
[Hint: required equation is |
\[{{x}^{2}}+{{y}^{2}}+\frac{b}{a}x+\frac{q}{p}y+\frac{c}{a}+\frac{c}{p}=0\]\[\Rightarrow \]B] |
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