A) \[I\,-\,A\]
B) \[{{(\,I\,-\,A\,)}^{-1}}\]
C) \[{{(\,I\,+\,A\,)}^{-1}}\]
D) none of these
Correct Answer: B
Solution :
\[{{A}^{3}}=O\] |
\[(I+A+{{A}^{2}})\,\,(I-A)=I-{{A}^{3}}=I\] |
\[\therefore \] \[I+A+{{A}^{2}}={{(I-A)}^{-1}}\] |
\[{{A}^{3}}=O\] |
now \[(I+A+{{A}^{2}})\,\,(I-A)=I-{{A}^{3}}=I\] |
\[\therefore \] \[I+A+{{A}^{2}}={{(I-A)}^{-1}}\] |
You need to login to perform this action.
You will be redirected in
3 sec