A) \[100{}^\circ C\]
B) \[103{}^\circ K\]
C) \[103{}^\circ C\]
D) \[50{}^\circ C\]
Correct Answer: C
Solution :
| Here, power \[=110kW={{10}^{4}}W\], mass \[m=8.0kg=8\times {{10}^{3}}g\],time\[t=2.5\min =2.5\times 60=150s\]and specific heat \[c=0.91J{{g}^{-1}}{}^\circ C\] |
| Total energy =power \[\times \]Time =\[{{10}^{4}}\times 150\operatorname{J}=\] As, \[50%\]of energy is lost. |
| Hence, thermal energy available, |
| \[\Delta Q=\frac{1}{2}\times 15\times {{10}^{5}}=7.5\times {{10}^{5}}J\] |
| As, \[\Delta Q=\operatorname{mc}\Delta \operatorname{T}\]\[\Rightarrow \]\[\Delta T=\frac{\Delta Q}{mc}=\frac{7.5\times {{10}^{5}}}{8\times {{10}^{3}}\times 0.91}=103{}^\circ C\] |
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