KVPY Sample Paper KVPY Stream-SX Model Paper-22

  • question_answer
    The flow of blood in a large artery of an anesthetised dog is diverted through a venturimeter. The wider part of the meter has a Cross-sectional area equal to that of the artery. \[A =8 m{{m}^{2}}\]. The narrower part has an area \[a=4m{{m}^{2}}\] and density of blood. i.e., \[\rho =~1.06\times {{10}^{3}} kg\,{{m}^{-3}}\]. The pressure drop in the artery is 24 Pa. What is the speed of the blood in the artery?

    A) 0.5 m/s

    B) 0.125m/s        

    C) 1.25 m/s

    D) 2.5 m/s

    Correct Answer: B

    Solution :

    Given, wides part of the meter cross-sectional area, \[A=8m{{m}^{2}}\] and narrow part, \[a=4m{{m}^{2}}\] and density of blood i.e., \[\rho \]is \[1.06\times {{10}^{3}}kg-{{m}^{-3}}\]. The ratio of the area is \[\left( \frac{A}{a} \right)=2.\] so, the speed of the blood in the artery i.e.,
    \[v=\sqrt{\frac{2\rho \,mgh}{\rho }}{{\left[ {{\left( \frac{A}{a} \right)}^{2}}-1 \right]}^{1/2}}\]\[\Rightarrow \]\[v=\sqrt{\frac{2\times 24Pa}{1060kg-{{m}^{-3}}\times ({{2}^{2}}-1)}}\]\[=0.125m{{s}^{-1}}\]

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