A) \[\frac{1}{18}\]
B) \[\frac{1}{9}\]
C) \[\frac{2}{9}\]
D) \[\frac{1}{36}\]
Correct Answer: C
Solution :
\[{{r}_{1}},{{r}_{2,}},{{r}_{3}}\in \{1,2,3,4,5,6\}\] \[{{r}_{1}},{{r}_{2,}},{{r}_{3}}\] are forms of \[\left( 3m,3m+1,3m+2 \right)\] \[\therefore \] Required probability\[=\frac{3!\times {}^{2}{{C}_{1}}\times {}^{2}{{C}_{1}}\times {}^{2}{{C}_{1}}}{{{6}^{3}}}=\frac{2}{9}\]You need to login to perform this action.
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