A) \[{}^{13}{{C}_{3}}\frac{12!}{5!3!2!}\]
B) \[\frac{13!}{5!313!2!}\]
C) \[\frac{14!}{3!3!2!}\]
D) None of these
Correct Answer: A
Solution :
All AAAAABBBDEEF can be arranged in\[\frac{12!}{5!3!2!}\] ways. Between the gaps C can be arranged \[{}^{13}{{C}_{3}}\] ways Total ways \[={}^{13}{{C}_{3}}\times \frac{12!}{5!3!2!}\]You need to login to perform this action.
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