| A particle of mass m initially at rest, is acted upon by a variable force F for a brief interval of time T. It attains a velocity u after the force stops acting. F is shown in the graph as a function of time. The curve is a semicircle, find u. |
 |
A) \[\frac{\pi {{F}_{0}}^{2}}{2m}\]
B) \[\frac{\pi {{T}^{2}}}{8m}\]
C) \[\frac{\pi {{F}_{0}}T}{4m}\]
D) \[\frac{{{F}_{0}}T}{2m}\]
Correct Answer: C
Solution :
Impulse = change in momentum \[\frac{\pi {{F}_{0}}T}{4}=mu-0\] \[u=\frac{\pi {{F}_{0}}T}{4m}\]
You need to login to perform this action.
You will be redirected in
3 sec
