A) \[Ga\]
B) \[Lu\]
C) \[La\]
D) \[Ta\]
Correct Answer: A
Solution :
| Gadolinium \[(Z=64)\] \[\left[ Xe \right]4{{f}^{7}},5{{d}^{1}},6{{s}^{2}}\] |
| Lutetium \[\left( Z=71 \right)\left[ Xe \right]4{{f}^{14}},5{{d}^{1}},6{{s}^{2}}\] |
| Lawrencium \[\left( Z=103 \right)\left[ Rn \right]5{{f}^{14}},6{{d}^{1}},7{{s}^{2}}\] |
| Tantalum \[\left( Z=73 \right)\left[ Xe \right]4{{f}^{14}},5{{d}^{3}},6{{s}^{2}}\] |
| Hence, gadolinium has got incompletely half-filled f-orbital. |
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