A) \[\ell +m=2\]
B) \[3\ell +m=4\]
C) \[3\ell -m=2\]
D) All of these
Correct Answer: D
Solution :
| If \[5x\ge 15\]i.e. \[x\ge 3,\]then |
| \[{{x}^{2}}-6x-5x+15-5=0\]i.e. \[{{x}^{2}}-11x+10=0\] i.e. \[x=1,\,\,\,10\] |
| \[\therefore \,\,\,\,x=10\] is a solution |
| If \[5x<15\]i.e. \[x<3,\]then \[{{x}^{2}}-6x+5x-15-5=0\]i.e. \[{{x}^{2}}-x-20=0\] i.e. \[x=5,\,\,-4\] |
| \[\therefore x=-\,4\] is a solution Thus \[\ell =1,\,\,\,m=1\] |
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