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KVPY Sample Paper KVPY Stream-SX Model Paper-24

  • question_answer
    A heat source at \[T={{10}^{3}}\] K is connected to another heat reservoir at \[T={{10}^{2}}\] K by a copper slab which is 1 m thick. Given that the thermal conductivity of copper is \[0.1\,W{{K}^{-1}}\,{{m}^{-1}},\] the energy flux through it in the steady state is:

    A) \[90\,W{{m}^{-2}}\]

    B) \[120\,W{{m}^{-2}}\]

    C) \[65\,W{{m}^{-2}}\]

    D) \[200\,\,W{{m}^{-2}}\]

    Correct Answer: A

    Solution :

    \[\frac{\Delta Q}{\Delta t}=\frac{kA}{\ell }({{T}_{2}}-{{T}_{1}})\] \[\frac{1}{A}\left( \frac{\Delta Q}{\Delta t} \right)=\frac{k}{\ell }({{T}_{2}}-{{T}_{1}}).\]


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