KVPY Sample Paper KVPY Stream-SX Model Paper-24

  • question_answer
                Total number of voids in 0.5 mole of a compound. Forming hexagonal closed packed structure are

    A) \[6.022\times {{10}^{23}}\]

    B) \[3.011\times {{10}^{23}}\]

    C) \[9.033\times {{10}^{23}}\]

    D) \[4.516\times {{10}^{23}}\]

    Correct Answer: C

    Solution :

    In hexagonal close packed structure, there are 6 atoms per unit cell.
    Number of octahedral voids = 6
    Number of tetrahedral voids \[=2\times 6=12\]
    Total number of voids \[=6+12=18\]
    Total number of voids per atom \[=\frac{18}{6}=3\]
    In 1 mole of a compound, the total number of voids \[=3\times 6.023\times {{10}^{23}}\]
    In \[0.5\]mole compound, the total number of voids\[=3\times 0.5\times 6.023\times {{10}^{23}}\]
    \[=9.034\times {{10}^{23}}\]


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