A) \[{{k}^{n}}-1\]
B) \[{{k}^{n}}\]
C) \[{{k}^{n}}+1\]
D) None of these
Correct Answer: D
Solution :
\[y=1\]\[\Rightarrow f(x)=f{{(1)}^{x}}\,\,\,i.e.\,\,\,f(x)={{k}^{x}}\]
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