| Two circles \[{{C}_{1}}\] and \[{{C}_{2}}\] intersect at two distinct points P & Q in a plane. Let a line passing through P meets circle \[{{C}_{1}}\] and \[{{C}_{2}}\] in A and B respectively. Let Y is mid-point of AB and QY meets circle \[{{C}_{1}}\] and \[{{C}_{2}}\] in X and Z respectively, then- |
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A) Y is trisection point of XZ
B) XY=3
C) XY=YZ
D) XY+YZ=3YZ
Correct Answer: C
Solution :
YP.YB=YZ.YQ YA. YP = YX. YQ take ratio, But YA=YB, Hence XY=YZ
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