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KVPY Sample Paper KVPY Stream-SX Model Paper-25

  • question_answer
    An uncharged capacitor of capacitance C is connected with an ideal cell. The emf of the cell is slowly increased from 0 to V (by some mechanism). The total energy taken from the cell in the process of charging of the capacitor is (assume the resistance of the circuit is very small):

    A) \[\frac{1}{2}C{{V}^{2}}\]

    B) \[2C{{V}^{2}}\]

    C) \[\frac{1}{4}C{{V}^{2}}\]

    D) \[C{{V}^{2}}\]

    Correct Answer: A

    Solution :

    The work done by cell\[=\int{Vdq}=\int\limits_{0}^{v}{CVdV}=\frac{1}{2}C{{V}^{2}}.\]


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