A) 6
B) 1
C) 4
D) 2
Correct Answer: C
Solution :
Since\[0\le \] arg (z) \[\le \frac{\pi }{4},\] represent the region of complex plane lying in the first quadrant and bounded by x-axis and the line y=x. \[\left| \,2z-4i\, \right|=2\left| \,z-2i\, \right|\] Least value of is\[\left| \,z-2i\, \right|\] length of perpendicular from (0, 2) to y=x which is \[\sqrt{2}.\] So the least value of \[\sqrt{2}\,\left| \,2z-4i\, \right|\]is 4.
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