question_answer

An inorganic compound [a] is formed on passing iodine gas through a concentrated liquor containing sodium sulphide and sodium sulphite. On adding a solution of [a] into the solution of cupric chloride, a white precipitate is formed which dissolves in excess of [a], forming a compound [b]. Hence, compound [b] is:

A) \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]

B) \[C{{u}_{2}}{{S}_{2}}{{O}_{3}}\]

C) \[[Cu\,{{(N{{H}_{3}})}_{4}}]\,S{{O}_{4}}\]

D) \[N{{a}_{4}}\,[C{{u}_{6}}\,{{({{S}_{2}}{{O}_{3}})}_{5}}]\]