A) \[N{{i}_{1.02}}{{O}_{1.00}}\]
B) \[N{{i}_{0.96}}{{O}_{1.00}}\]
C) \[N{{i}_{0.98}}{{O}_{0.98}}\]
D) \[N{{i}_{0.98}}{{O}_{1.00}}\]
Correct Answer: D
Solution :
| \[{{d}^{8}}\to N{{i}^{2+}}.{{d}^{7}}\to N{{i}^{3+}}\] |
| Total charge of nickel. |
| \[(0.96\times 2)+(0.04\times 3)=2.04\] |
| No. of \[{{O}^{2-}}\]ion = \[=\frac{2.04}{2}=1.02.\] |
| Formula of solid =\[Ni{{O}_{1.02}}=N{{i}_{0.98}}O.\] |
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