question_answer

In ground state of P if four quantum no. are \[(4,1,0,-1/2)\,\] (for last \[{{e}^{-}}\]) then calculate the quantum no. of last \[{{e}^{-}}\] in excited state of P-

A) \[4,2,0,+\,1/2\]

B) \[4,\text{ }2,\text{+1},+1/2\]

C) \[{{N}_{2}}\]

D) All are correct

Correct Answer: B

Solution :

\[p=3{{s}^{2}}3{{p}^{3}}\]

In excited state spin quantum no. of last \[{{e}^{-}}\] will be\[(-1/2),\] To obey Pauli's exclusion principle