A) \[\frac{4\pi }{3}\]
B) \[\frac{3}{8}\pi \]
C) \[\frac{8\pi }{3}\]
D) \[\frac{7}{3}\pi \]
Correct Answer: C
Solution :
| \[|{{v}_{4}}|=|{{a}_{4}}|\]\[\Rightarrow \]\[{{\left( w\sqrt{{{A}^{2}}-{{x}^{2}}} \right)}_{4}}={{({{w}^{2}}x)}_{4}}\]\[\Rightarrow \]\[w\sqrt{25-16}={{w}^{2}}\times 4\]\[\Rightarrow \]\[w=\frac{3}{4}\] |
| \[T=\frac{2\pi }{w}\] |
| \[=2\pi \frac{4}{3}=\frac{8\pi }{3}.\] |
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