A) \[\frac{1}{512}\]
B) \[\frac{1}{1024}\]
C) \[\frac{1}{256}\]
D) \[\frac{1}{2}\]
Correct Answer: A
Solution :
Using formula\[\frac{\sin {{2}^{n}}A}{{{2}^{n}}\sin A}\] \[=\cos A\cos 2A\cos {{2}^{2}}A...\cos {{2}^{n-1}}A\]You need to login to perform this action.
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