• # question_answer Two sides of a parallelogram are along the lines, $x+y=3$ and $x-y+3=0.$ If its diagonals intersect at $\left( 2,4 \right),$ then one of its vertex is: A) $\left( 3,5 \right)$ B) $\left( 2,1 \right)$ C) $\left( 2,6 \right)$ D) $\left( 3,6 \right)$

 Intersection point is A(0, 3) $M=(4,6)$ $M\Rightarrow (1,2),D\to (3,6)$