KVPY Sample Paper KVPY Stream-SX Model Paper-29

  • question_answer
    A satellite with mass 2000 kg and angular momentum magnitude \[2\times {{10}^{12}}kg.{{m}^{2}}/s\] is moving in an elliptical orbit around a planet. The rate at which area is being swept out by the satellite around the planet, is equal to

    A) \[1\times {{10}^{9}}{{m}^{2}}/s\]

    B) \[5\times {{10}^{9}}{{m}^{2}}/s\]

    C) \[5\times {{10}^{8}}{{m}^{2}}/s\]     

    D) \[4\times {{10}^{15}}{{m}^{2}}/s\]

    Correct Answer: C

    Solution :

    \[\frac{dA}{dt}=\frac{L}{2m}\,\,\,\,\,\,=\frac{2\times {{10}^{12}}}{2\times 2000}=5\times {{10}^{8}}\,\,{{m}^{2}}/s\]

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