• question_answer A satellite with mass 2000 kg and angular momentum magnitude $2\times {{10}^{12}}kg.{{m}^{2}}/s$ is moving in an elliptical orbit around a planet. The rate at which area is being swept out by the satellite around the planet, is equal to A) $1\times {{10}^{9}}{{m}^{2}}/s$ B) $5\times {{10}^{9}}{{m}^{2}}/s$ C) $5\times {{10}^{8}}{{m}^{2}}/s$      D) $4\times {{10}^{15}}{{m}^{2}}/s$

$\frac{dA}{dt}=\frac{L}{2m}\,\,\,\,\,\,=\frac{2\times {{10}^{12}}}{2\times 2000}=5\times {{10}^{8}}\,\,{{m}^{2}}/s$