KVPY Sample Paper KVPY Stream-SX Model Paper-29

  • question_answer
    For a homogeneous gaseous reaction \[\operatorname{A}\xrightarrow{{}}3B,\], if pressure after time t was \[{{\operatorname{P}}_{t}}\] and after completion of reaction, pressure was \[{{\operatorname{P}}_{\infty }}\] then select correct relation

    A) \[\operatorname{k}=\frac{1}{t}ln\left( \frac{{{P}_{\infty }}}{3\left( {{P}_{\infty }}-{{P}_{t}} \right)} \right)\]

    B) \[\operatorname{k}=\frac{1}{t}ln\left( \frac{2{{P}_{\infty }}}{\left( {{P}_{\infty }}-{{P}_{t}} \right)} \right)\]

    C) \[\operatorname{k}=\frac{1}{t}ln\left( \frac{3{{P}_{\infty }}}{2{{P}_{\infty }}-{{P}_{\operatorname{t}}}} \right)\]

    D) \[\operatorname{k}=\frac{1}{t}ln\left( \frac{2{{P}_{\infty }}}{3\left( {{P}_{\infty }}-{{P}_{\operatorname{t}}} \right)} \right)\]

    Correct Answer: D

    Solution :

    \[{{P}_{T}}={{P}_{0}}+2x\]
    \[x=\frac{{{P}_{T}}{{P}_{0}}}{2}\]
    \[k=\frac{1}{t}\ln \left( \frac{{{P}_{0}}}{{{P}_{0}}-x} \right)\]
    After long time,
    \[x=\frac{{{P}_{T}}-\frac{{{P}_{\infty }}}{3}}{2}\]
    \[k=\frac{1}{t}\ln \left( \frac{\frac{{{P}_{\infty }}}{3}}{\frac{{{P}_{\infty }}}{3}-\left( \frac{3{{P}_{T}}-{{P}_{\infty }}}{6} \right)} \right)\]
    \[{{P}_{\infty }}=3{{P}_{O}},x=\frac{3{{P}_{T}}-{{P}_{\infty }}}{6}\]
    \[k=\frac{1}{t}\ln \left( \frac{{{P}_{\infty }}/3}{\frac{{{P}_{\infty }}}{2}-\frac{{{P}_{T}}}{2}} \right)\]
    \[k=\frac{1}{t}\ln \left( \frac{2{{P}_{\infty }}}{3\left( {{P}_{\infty }}-{{P}_{T}} \right)} \right)\]


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