• # question_answer In $\operatorname{O}_{2}^{-},{{\operatorname{O}}_{2}}$ and $\operatorname{O}_{2}^{2-}$ molecular species, that total number of antibonding electrons respectively are  A) 7, 6, 8 B) 1, 0, 2 C) 6, 6, 6 D) 8, 6, 8

 Molecular orbital electronic configuration of these species are : $\operatorname{O}_{2}^{-}\left( 17{{e}^{-}} \right)=\sigma 1{{\operatorname{s}}^{2}},\sigma *1{{s}^{2}},\sigma 2{{s}^{2}},\sigma *2{{s}^{2}},\sigma 2\operatorname{p}_{z}^{2},$$\pi 2p_{x}^{2}=\pi 2\operatorname{p}_{y}^{2},\pi *2\operatorname{p}_{x}^{2}=\pi *2\operatorname{p}_{y}^{1}$ ${{O}_{2}}\left( 16{{e}^{-}} \right)=\sigma 1{{\operatorname{s}}^{2}},\sigma *1{{s}^{2}},\sigma 2{{\operatorname{s}}^{2}},\sigma *2{{\operatorname{s}}^{2}},\sigma 2\operatorname{p}_{z}^{2},$$\pi 2\operatorname{p}_{x}^{2}=\pi 2\operatorname{p}_{y}^{2},\pi *2p_{x}^{1}=\pi *2p_{y}^{1}$ $\operatorname{O}_{2}^{2-}\left( 18{{e}^{-}} \right)=\sigma 1{{\operatorname{s}}^{2}},\sigma *1{{\operatorname{s}}^{2}},\sigma 2{{\operatorname{s}}^{2}},\sigma *2{{\operatorname{s}}^{2}},\sigma 2\operatorname{p}_{z}^{2}$ $\pi 2\operatorname{p}_{x}^{2}=\pi 2\operatorname{p}_{y}^{2},\pi *2\operatorname{p}_{x}^{2}=\pi *2\operatorname{p}_{y}^{2}$ Hence number of antibonding electrons are 7, 6 and 8 respectively.