A) 7, 6, 8
B) 1, 0, 2
C) 6, 6, 6
D) 8, 6, 8
Correct Answer: A
Solution :
| Molecular orbital electronic configuration of these species are : |
| \[\operatorname{O}_{2}^{-}\left( 17{{e}^{-}} \right)=\sigma 1{{\operatorname{s}}^{2}},\sigma *1{{s}^{2}},\sigma 2{{s}^{2}},\sigma *2{{s}^{2}},\sigma 2\operatorname{p}_{z}^{2},\]\[\pi 2p_{x}^{2}=\pi 2\operatorname{p}_{y}^{2},\pi *2\operatorname{p}_{x}^{2}=\pi *2\operatorname{p}_{y}^{1}\] |
| \[{{O}_{2}}\left( 16{{e}^{-}} \right)=\sigma 1{{\operatorname{s}}^{2}},\sigma *1{{s}^{2}},\sigma 2{{\operatorname{s}}^{2}},\sigma *2{{\operatorname{s}}^{2}},\sigma 2\operatorname{p}_{z}^{2},\]\[\pi 2\operatorname{p}_{x}^{2}=\pi 2\operatorname{p}_{y}^{2},\pi *2p_{x}^{1}=\pi *2p_{y}^{1}\] |
| \[\operatorname{O}_{2}^{2-}\left( 18{{e}^{-}} \right)=\sigma 1{{\operatorname{s}}^{2}},\sigma *1{{\operatorname{s}}^{2}},\sigma 2{{\operatorname{s}}^{2}},\sigma *2{{\operatorname{s}}^{2}},\sigma 2\operatorname{p}_{z}^{2}\] |
| \[\pi 2\operatorname{p}_{x}^{2}=\pi 2\operatorname{p}_{y}^{2},\pi *2\operatorname{p}_{x}^{2}=\pi *2\operatorname{p}_{y}^{2}\] |
| Hence number of antibonding electrons are 7, 6 and 8 respectively. |
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