A) 454
B) 804
C) 852
D) 910
Correct Answer: D
Solution :
| For \[bcc,\] |
| \[d=\frac{\sqrt{3}}{2}a\,\text{or}\,a=\frac{2d}{\sqrt{3}}=\frac{2\times 4.52}{1.732}=5.219\overset{\text{o}}{\mathop{\text{A}}}\,=522pm\]\[\rho =\frac{\operatorname{Z}\times M}{{{\operatorname{a}}^{3}}\times {{\operatorname{N}}_{A}}\times {{10}^{-30}}}\]\[=\frac{2\times 39}{{{\left( 522 \right)}^{3}}\times \left( 6.023\times {{10}^{23}} \right)\times {{10}^{-30}}}\] |
| \[=0.91g/c{{m}^{3}}=910kg\,{{m}^{-3}}\] |
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