• # question_answer Arrange the (C - H) bonds x, y and z in decreasing order of their bond dissociation energies in homolysis. A) $y>x>z$ B) $z>x>y$ C) $z>y>x$ D) $y>z>x$

 So bond dissociation enegy order is ${{\operatorname{E}}_{1}}<{{E}_{2}}<{{E}_{3}}i.e,\left( z \right)>\left( x \right)>\left( y \right)$