KVPY Sample Paper KVPY Stream-SX Model Paper-29

  • question_answer
    Consider the following reaction: \[M{{X}_{4}}+X{{'}_{2}}\xrightarrow{{}}M{{X}_{4}}X{{'}_{2}}\]
    If atomic number of M is 52 and X and X' are halogens and X' is more electronegative than X. Then choose correct statement regarding given information:

    A) Both X' atoms occupy axial positions which are formed by overlapping of p and \[d\]-orbitals only

    B) All M - X bond lengths are identical in both \[{{\operatorname{MX}}_{4}}\] and \[{{\operatorname{MX}}_{4}}X'{{  }_{2}}\] compounds

    C) Central atom 'M' does not use non-axial set of \[d\]-orbital in hybridization of final product.

    D) Hybridization of central atom 'M' remains same in both reactant and final product.

    Correct Answer: C

    Solution :

    Hybridization of \[\operatorname{Te}:s{{p}^{3}}d\]
    In the above compound orbitals used hybridization of Te are oxial t.e\[s,{{p}_{x}}^{,}{{p}_{y}},{{p}_{z}}^{,}\]
    All M?X bond lengths are identical.
    Hybridization of Te: \[s{{p}^{3}}{{d}^{2}}\]
    In the above comopound orbitals used in the hybridization of Te are \[s,{{p}_{x}},{{p}_{y}},{{p}_{z}},{{d}_{{{z}^{2}}}}.\]
    All M?X bond lengths are not identical,

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