• # question_answer The correct order of magnetic moments (spin only values in B.M.) among is A) ${{[Fe{{(CN)}_{6}}]}^{4-}}>{{[MnC{{l}_{4}}]}^{2-}}>{{[CoC{{l}_{4}}]}^{2-}}$ B) ${{[MnC{{l}_{4}}]}^{2-}}>{{[Fe{{(CN)}_{6}}]}^{4-}}>{{[CoC{{l}_{4}}]}^{2-}}$ C) ${{[MnC{{l}_{4}}]}^{2-}}>{{[CoC{{l}_{4}}]}^{2-}}>{{[Fe{{(CN)}_{6}}]}^{4-}}$ D) ${{[Fe{{(CN)}_{6}}]}^{4-}}>{{[CoC{{l}_{4}}]}^{2-}}>{{[MnC{{l}_{4}}]}^{2-}}$             (Atomic nos.: Mn=25, Fe=26, Co=27)

 No. of unpaired electrons = 0 No. of unpaired electrons = 5 No. of unpaired electrons = 3 The greater the number of unpaired electrons, greater the magnitude of magnetic moment. Hence the correct order will be ${{[MnC{{l}_{4}}]}^{2-}}>{{[CoC{{l}_{4}}]}^{2-}}>{{[Fe{{(CN)}_{6}}]}^{4-}}$s