A) three
B) two
C) four
D) one
Correct Answer: B
Solution :
\[\left| \begin{matrix} \sin 3\theta & -1 & 1 \\ \cos 2\theta & 4 & 3 \\ 2 & 7 & 7 \\ \end{matrix} \right|=0\] |
\[7\sin 3\theta +14\cos 2\theta -14=0\] |
\[\sin 3\theta +2\cos 2\theta -2=0,\sin \theta =\frac{1}{2}.\] |
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