• # question_answer On which of the following lines lies the point of intersection of the line, $\frac{x-4}{2}=\frac{y-5}{2}=\frac{z-3}{1}$ and the plane, $x+y+z=2?$ A) $\frac{x+3}{3}=\frac{4-y}{3}=\frac{z+1}{-2}$            B) $\frac{x-4}{1}=\frac{y-5}{1}=\frac{z-5}{-1}$ C) $\frac{x-1}{1}=\frac{y-3}{2}=\frac{z+4}{-5}$ D) $\frac{x-2}{2}=\frac{y-3}{2}=\frac{z+3}{3}$

Correct Answer: C

Solution :

 Put$(2\lambda +4,2\lambda +5,\lambda +3)$in$x+y+z=2$ $2\lambda +4+2\lambda +5+\lambda +3=2$ $5\lambda =-10$           $\lambda =-2$ $P(0,1,1)$ Now put in options Answer is C.

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