question_answer

Two sides of a parallelogram are along the lines, \[x+y=3\] and \[x-y+3=0.\] If its diagonals intersect at \[\left( 2,4 \right),\] then one of its vertex is:

A) \[\left( 3,5 \right)\]

B) \[\left( 2,1 \right)\]

C) \[\left( 2,6 \right)\]

D) \[\left( 3,6 \right)\]

Correct Answer: D

Solution :

Intersection point is A(0, 3)

\[M=(4,6)\]

\[M\Rightarrow (1,2),D\to (3,6)\]