• # question_answer In the shown figure a battery (ideal) is joined between terminals A and B having EMF=E. Find the current supplied by the battery : A) $\frac{8E}{R}$ B) $\frac{8E}{3R}$ C) $\frac{4E}{R}$ D) $\frac{4E}{3R}$

Solution :

 As potential of points ${{O}_{1}},{{O}_{2}},{{O}_{3}}$and ${{O}_{4}}$ is same Hence, Equivalent circuit. $\Rightarrow {{R}_{eq.}}=\frac{3R}{8}$           Hence, $\therefore \,\,I=\frac{8E}{3R}$

You need to login to perform this action.
You will be redirected in 3 sec