A) Monoatomic
B) polyatomic
C) Diatomic
D) data insufficient
Correct Answer: C
Solution :
[C]\[dU=\frac{dW}{2}\] |
By 1st law \[\to dQ=3dU=3n{{C}_{\text{v}}}dT\] |
Molar heat capacity \[C=\frac{dQ}{ndT}=3{{C}_{\text{v}}}\] |
Given \[C=\frac{15R}{2}\] |
\[\therefore {{C}_{\text{v}}}=\frac{5}{2}R\] |
\[\therefore \]Degree of freedom =5 |
so gas is diatomic. |
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