A) \[{{L}_{4}}<{{L}_{3}}<{{L}_{2}}<{{L}_{1}}\]
B) \[{{L}_{1}}<{{L}_{2}}<{{L}_{3}}<{{L}_{4}}\]
C) \[{{L}_{3}}<{{L}_{2}}<{{L}_{4}}<{{L}_{1}}\]
D) \[{{L}_{1}}<{{L}_{2}}<{{L}_{4}}<{{L}_{3}}\]
Correct Answer: B
Solution :
[b] For a given metal ion, weak field ligands create a complex with smaller A, which will absorbs light of longer X and thus lower frequency. Conservely, stronger field ligands create a larger A, absorb light of shorter \[\lambda \] and thus higher v i.e. higher energy. \[\underset{\lambda \,\,=\,\,650\,\,nm}{\mathop{Red}}\,<\text{ }\underset{570\,\,nm}{\mathop{yellow}}\,\text{ }<\text{ }\underset{490\,\,nm}{\mathop{green\text{ }}}\,<\,\,\underset{450\,\,nm}{\mathop{Blue}}\,~\] So order of ligand strength is \[{{L}_{1}}<{{L}_{3}}<{{L}_{2}}<{{L}_{4}}\]You need to login to perform this action.
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