A) malachite
B) bauxite
C) calamine
D) siderite
Correct Answer: B
Solution :
| Malachite\[=CuC{{O}_{3}}.Cu{{(OH)}_{2}}\] |
| Bauxite \[=A{{l}_{2}}{{O}_{3}}.2{{H}_{2}}O\]or \[Al{{O}_{x}}.{{(OH)}_{3-2x}}\] |
| (where\[D<x<1\]) |
| Calamine \[=ZnC{{O}_{3}}\] |
| Siderite \[=FeC{{O}_{3}}\] |
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