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KVPY Sample Paper KVPY Stream-SX Model Paper-30

  • question_answer
    In rabbits, two genes A and B are present on two different chromosomes. Products of both wild type A and B genes are essential for normal hearing. Homozygous recessive mutants either for A, B or both results in deafness. If a double heterozygous male (AaBb) is crossed with a double heterozygous female, the ratio of phenotypically normal and deaf rabbits will be:

    A) \[15:1\]

    B) \[7:9\]

    C) \[9:7\]   

    D) \[13:3\]

    Correct Answer: C

    Solution :

    Parents: AaBb\[\times \]AaBb Offsprings:
    AB Ab aB ab
    AB AABB Normal hearing AABb Normal hearing AaBB Normal hearing AaBb Normal hearing
    Ab AABb Normal hearing  AAbb Deaf AaBb Normal hearing  Aabb Deaf
    aB AaBB Normal hearing AaBb Normal hearing aaBB Deaf aaBb Deaf
    ab AaBb Normal hearing Aabb Deaf aaBb Deaf Aabb Deaf
    Phenotypic ratio = Normal hearing: Deaf = 9:7


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